
Main
Date: 15 May 2005 22:02:55
From: Douglas Yee
Subject: Reinfeld's _1001 Brilliant Ways to Checkmate_

I'm finally making my way through this old classic and had a a question about Problem #548: [FEN "r3nr1k/ppqbNpp1/7p/2p1p3/2B4Q/P4P2/1PP4P/2KR2R1 w   0 1"] The answer Reinfeld gives (translating from descriptive) is 1.Rxg7 Kxg7 (1.Nxg7 2.Qxh6++) 2.Rg1+ Kh7 3.Bd3+ f5 4.Rg6 any 5.Qxh6++. Black can delay mate for a few more moves by playing 3.e4 instead of 3.f5, but if 1.Qb6 is played instead of 1.Kxg7, is there still a forced mate? Problem #513 turned out to be a very interesting study: [FEN "r1b2rk1/pp1p1pp1/1q1n2np/2b3NQ/2B1N3/8/PP3PPP/R1B2RK1 w   0 1"] 1.Qxg6 is the obvious first move in the sequence, but where to go from here? Reinfeld gives the straightforward solution 1.Qxg6 hxg5 2.Nf6+ Kh8 3.Qh7++. But what if 1.Re8 instead? After thinking about it for a while and giving up, I ran the position through ChestUCI which eventually came back with two main Mate in 9 lines. The second line is particularly impressive: A) 1.Qxg6 Re8 2.Nxd6 Qxd6 3.Qxf7+ Kh8 4.Qxe8+ Qf8 5.Qg6 Qg8 6.Bxg8 Kxg8 7.Qf7+ Kh8 8.Qe8 Bf8 9.Qxf8++ B) 1.Qxg6 Re8 2.Bf4 Re6 3.Bxe6 Qd8 4.Be5 Bxf2+ 5.Rxf2 Nf5 6.Nf6+ Qxf6 7.Bxf6 h5 8.Bxf7+ Kh8 9.Qh7++ I actually came close to finding A) on my own but had problems visualizing the board towards the end of the sequence. B) seems to be the sort of solution only a computer would likely find.  Douglas



Date: 16 May 2005 16:00:02
From: Antonio Torrecillas
Subject: Re: Reinfeld's _1001 Brilliant Ways to Checkmate_

En/na Douglas Yee ha escrit: > Problem #513 turned out to be a very interesting study: > [FEN "r1b2rk1/pp1p1pp1/1q1n2np/2b3NQ/2B1N3/8/PP3PPP/R1B2RK1 w   0 1"] > > 1.Qxg6 is the obvious first move in the sequence, but where to go > from here? Reinfeld gives the straightforward solution 1.Qxg6 hxg5 > 2.Nf6+ Kh8 3.Qh7++. But what if 1.Re8 instead? After thinking > about it for a while and giving up, I ran the position through > ChestUCI which eventually came back with two main Mate in 9 > lines. The second line is particularly impressive: > > A) 1.Qxg6 Re8 2.Nxd6 Qxd6 3.Qxf7+ Kh8 4.Qxe8+ Qf8 5.Qg6 Qg8 > 6.Bxg8 Kxg8 7.Qf7+ Kh8 8.Qe8 Bf8 9.Qxf8++ > > B) 1.Qxg6 Re8 2.Bf4 Re6 3.Bxe6 Qd8 4.Be5 Bxf2+ 5.Rxf2 Nf5 > 6.Nf6+ Qxf6 7.Bxf6 h5 8.Bxf7+ Kh8 9.Qh7++ > > I actually came close to finding A) on my own but had problems > visualizing the board towards the end of the sequence. B) seems > to be the sort of solution only a computer would likely find. When playing a game 1...Re8 is not a move to consider because white is a piece up and has an strong attack. In that case white do not need to find a mate in 9 and surely black would resign in a few moves. I suppose reinfeld solution was the line played with only "relevant" lines added. AT


Date: 16 May 2005 11:49:14
From: Reinhold Stansich
Subject: Re: Reinfeld's _1001 Brilliant Ways to Checkmate_

Douglas Yee schrieb: > I'm finally making my way through this old classic and had a > a question about Problem #548: > [FEN "r3nr1k/ppqbNpp1/7p/2p1p3/2B4Q/P4P2/1PP4P/2KR2R1 w   0 1"] > > The answer Reinfeld gives (translating from descriptive) is > 1.Rxg7 Kxg7 (1.Nxg7 2.Qxh6++) 2.Rg1+ Kh7 3.Bd3+ f5 4.Rg6 any > 5.Qxh6++. Black can delay mate for a few more moves by playing > 3.e4 instead of 3.f5, but if 1.Qb6 is played instead of > 1.Kxg7, is there still a forced mate? IMHO 2. Rg6 leads to mate soon. Black has to take with 2...Qxg6 3. Nxg6 and mate to follow in a few moves. Regards Reini

